30=0.005q^2

Solution for 30=0.005q^2 equation:

30=0.005q^2

We move all terms to the left:

30-(0.005q^2)=0

We get rid of parentheses

-0.005q^2+30=0

a = -0.005; b = 0; c = +30;
Δ = b2-4ac
Δ = 02-4·(-0.005)·30
Δ = 0.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.6}}{2*-0.005}=\frac{0-\sqrt{0.6}}{-0.01}
=-\frac{\sqrt{}}{-0.01}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.6}}{2*-0.005}=\frac{0+\sqrt{0.6}}{-0.01}
=\frac{\sqrt{}}{-0.01}
$